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9x^2-18xy+5y^2
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factor please
one way of tackling these is as follows: 1. this expression involves x and y, so we know the solution has to be of the form: (ax+by)(cx+dy) 2. the coefficient of y^2 is 5 (which is a prime number) and the middle term involving xy is negative, so we know the factorisation must be of the form: (ax-5y)(bx-y) 3. that leaves a and b to be found. the coefficient of x^2 is 9 which can be factored as 1*9 or 3*3. you should be able to solve from here.
(3x+5y)?
we ended up with (ax-5y)(bx-y) so (3x+5y) cannot be one of the factors - it has to be (3x-5y). now what is the remaining factor?
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