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how to solve this system of equations with substitution? y= 4x x + y = 5
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X+4X=5 5X=5 5/5=1 X=1
y = 4x is equation1. x + y = 5 can also be written to make y the subject. y = 5 - x is equation 2 EQUATION 1 --> y = 4x EQUATION 2 --> y = 5 - x This basically means: 4x = 5 - x 4x + x = 5 5x = 5 x = 1
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