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Mathematics 14 Online
OpenStudy (anonymous):

Find the integral from -1 to 1 for (1/(1+y^2))dy

OpenStudy (anonymous):

\[\int\limits_{-1}^{1}(1/(1+y^2))dy\]

OpenStudy (anonymous):

arctan^-1(y) from -1 to 1 = pi/2

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