Question

find the indefinite integral using substitutions:
x sin 3x^2 dx

Answer 1

let u=3x^2, du = 6x
so...our integral is
\[1/6\int\limits_{}^{}sinudu\]
which is
\[-\cos(u)/6 + C\]
sub back in for u = 3x^2
\[-1/6\cos(3x^2)+C\]