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OpenStudy (anonymous):
IN the circuit shown in the figure??
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OpenStudy (anonymous):
OpenStudy (kropot72):
Note the polarity of the two batteries. The batteries are in series with a total voltage of: 2.5 + 3.4 = 5.9V The current through R1 which has the combined voltage of the two batteries in series across it is: 5.9/3.4 = 1.735 amps
OpenStudy (anonymous):
so R1 got when we solve the right part of circuit ?
OpenStudy (kropot72):
The presence of R2 in the circuit does not affect current through R1. If R2 was removed the current in R1 would stay the same.
OpenStudy (anonymous):
ok, thanks :)
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OpenStudy (kropot72):
You're welcome.
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