A right triangle has an area of 30 square inches. Express the perimeter P of the rectangle (sum of the hypotenuse and the two legs) as a function of the length, x, of one of its legs.
A) 2x+2sqrtx B)x+(30/x)+sqrt[x^2+(30/x)^2] C) (30/sqrt[x^2+y^2]) D) x+(60/x)+sqrt[x^2+(60/x)^2] E) A=2x+(60/x)
|dw:1335330028142:dw| area of a triangle is equal to
1/2 base * height
what rectangle?
Exactly my point. I'm looking at a problem with no diagram.
can you double check you copied correctly, word for word
Just checked and everything was typed out as is noted on my paper. I believe the professor might have made a mistake. I have found a couple today.
he probably means to draw a rectangle inside the triangle
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Okay, you're probably right. But what can I do from there?
oh, theres a typo
@di.gracia sum of the hypotenuse and the two legs
it should say triangle, not rectangle
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