Question

the quantity 4+radical 8 times the quantity 4 minus 4 radical 8.

Answer 1

\[{{(4+\sqrt{8})} \times {(4-{4}\sqrt{8})}}\]

Answer 2

is this your question?

Answer 3

yes it is

Answer 4

plz see the second term once

Answer 5

take to second 4 away ,just leave one 4

Answer 6

\[{4^2 - \sqrt{8^2}}= 16 - 8 = 8\]

Answer 7

(4 + sqrt8)*(4-sqrt8) = 4^2 -(sqrt8)^2 = 16 - 8 = 8

Answer 8

thanks :)