Question

the quantity 7+3 radical 2 times the quantity 9 minus 5 radical 2.

Answer 1

\[(7+3\sqrt{2})\times(9 - 5\sqrt{2})\]

this is a binomial product problem
\[7\times9 - 7\times5\sqrt{2} + 9\times 3\sqrt{2} + 3\times-5\times \sqrt{2}\times \sqrt{2}\]


simplifying gives

\[63 - 8\sqrt{2} - 30\]

final answer

\[33 - 8\sqrt{2}\]

Answer 2

thank you very much :)