Question

pls show me how to do this...

\(\LARGE \int \frac{\sqrt{\tan x}}{1 - \sin ^2 x} dx\)

Answer 1

it looks easy...but i have no idea what to do @_@

Answer 2

oh wait...i saw it lol...how foolish of me to have not seen that thanks @integralsabiti

Answer 3

ok u can do it :D

Answer 4

let u = \(\sqrt {tanx }\)
u^2 = tanx
2udu = sec^2 x

\(\int u(2udu)\)
\(\int 2u^2 du\)

\(\LARGE \frac{2u^3}{3}\)

\(\LARGE \frac{2\tan x \sqrt{tanx}}{3}\)

Answer 5

:)

Answer 6

abselutelyy

Answer 7

how foolish of me to not have seen that lol

Answer 8

It happens sometime :D