Question

Non-interesting integration question #3

Answer 1

Actually... It's the next part of the previous question :S
How can we related (d) to the previous part so that we can solve (d) easier?

Answer 2

looks like we can use the setup in C for something; it looks to have the same kind of elements

Answer 3

I though g(x) = cosx / (1+sinx)^2. ...

Answer 4

does:\[\frac{cos(pi-x)}{(1+sin(pi-x))^2}=-\frac{cos(x)}{(1+sin(x))^2}\]???

Answer 5

whoa .. that goes smoothly!!

Answer 6

Which part of the result are you using?

Answer 7

ln( 1 + e^(cos pi - x)) = ln( 1 + e^-(cos x)) = ln (e^cosx + 1) - ln e^cos x

^^^ the up would be -g(x)

Answer 8

So, it's from (c), in the question...