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Mathematics 19 Online
OpenStudy (anonymous):

What is the factored form of the expression? 12d2 + 4d – 1 A. (6d + 1)(2d + 1) B. (6d – 1)(2d – 1) C. (6d – 1)(2d + 1) D. (6d + 1)(2d – 1)

OpenStudy (anonymous):

C

OpenStudy (anonymous):

c

OpenStudy (anonymous):

it was c

sam (.sam.):

12d^(2)+4d-1 (d+(1)/(2))(d-(1)/(6)) (2d+1)(6d-1)

OpenStudy (anonymous):

C. (6d – 1)(2d + 1) I got this correct on my test.

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