Question

domain of..
(x-7) (x-3) (x+5)
---------------
|(x-4)| (x-1)

i.e. { (x-7) . (x-3) . (x+5) } / { |(x-4)| . (x-1) }

Answer 1

(-infinity, 1) union (1, 4) union (4, infinity)

Answer 2

sorry, that should be:
domain of..
(x-7) (x-3) (x+5)
--------------- <= 0
|(x-4)| (x-1)

i.e. { (x-7) . (x-3) . (x+5) } / { |(x-4)| . (x-1) } <= 0

<= means less than or equal to
and that is modulus sign