Question

solve: 2log7-log(x+3)=2

Answer 1

start by
\[\log(7^2)-\log(x+3)=2\] then
\[\log(\frac{49}{x+3})=2\]\ and finally write in equivalent exponential form as
\[\frac{49}{x+3}=10^2=100\]

Answer 2

thank u

Answer 3

yw