Question

lim[x:1,(x^(3) - 1)/(x^(2)-6x+5)]

Answer 1

you the fact that you can factorise this expression as follows:\[\frac{x^3-1}{x^2-6x+5}=\frac{\cancel{(x-1)}(x^2+x+1)}{\cancel{(x-1)}(x-5)}=\frac{x^2+x+1}{x-5}\]

Answer 2

thank so much....i made a mistake because (x-1) ( x^2 +2x+1)....:) god bless u

Answer 3

you're welcome

Answer 4

thank u for ur help

Answer 5

no problem at all - I'm glad I was able to help :)

Answer 6

:)