The equation of line k is y = -1/5x – 1/8. What is the equation of the line that is perpendicular to line k and passes through (0, 0)?

Question

anonymous · Answer

y = 5x

Exp.
The slope of given line is -(1/5)
Slope of line perp. to it will be 5(because product of slopes of 2 perp. lines is -1)
Equation of line passing through a given point is:
y - a = m(x-b)  (where a and b are the ordinate and abscissa)
there fore the solution willl be 
y - 0 = 5(x-0)
y = 5x