Question

has this equation been factored completely and correctly ?
x^5-16x^3=8x^2-128
x^3(x^2-16) + 8(x^2-16)
(x^2-16)(x^3+8)

Answer 1

(x^2-16) is of the form (a^2 - b^2)
so (x^2 - 16) can factor into (x-4)(x+4)