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Mathematics 13 Online
OpenStudy (anonymous):

factor.show work please. 4xy^2-7y

OpenStudy (anonymous):

\[4xy^{2} - 7y\] See what is common in both terms, that is 'y' So basically what you have in the beginning is 4xyy-7y From this you can take 'y' common. You will be left with y*(4xy - 7) Answer

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