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Mathematics 16 Online
OpenStudy (anonymous):

2x^2+12x+16 factor

OpenStudy (anonymous):

2 (2+x) (4+x)

OpenStudy (anonymous):

2x^2+ 8x+4x+16=0

OpenStudy (anonymous):

ok ms moon, guess what the first step is again?

OpenStudy (anonymous):

common factor of 2, start with \(2(x^2+6x+8)\)

OpenStudy (anonymous):

then you see that \(2\times 4=8\) and \(2+4=6\) so you get \[2(x+2)(x+4)\]

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