Question

If f(x) = x^2-3x and g(x) = [(square root)(x)] - 1

f(g(x)) =

Answer 1

f(g(x)=(squareroot x -1)^2-3(squarerootx-1)
=x+1-2squarerootx-3squarerootx+3
x+4-5squarerootx

Answer 2

is this the answer katlvb

Answer 3

no it isn't :(

Answer 4

the last number is off

Answer 5

write the answer here

Answer 6

the choices are
x-5 times (square root x);
x-5 times (square root x)-2;
x-5 times (square root x) + 4

Answer 7

x-3 times (square root x)+2;
x-3 times (square root x)+4

Answer 8

how do you distribute the f{[(square root x)-1][x^2-3x]?

Answer 9

its x-5times (square rootx)+4