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Find the exact value of the area under one arch of the curve y(t) = V0sin(wt). Assume V0 and w are positive constants. You can use V_0 for V0. Note - V is upper case here.
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|dw:1335423831383:dw| is that what you ask ??
i have no idea i try doing it from ov to pi but the answer was wrong
also i did it from -2pi/2 to 3pi/2 but it was wrong too so idk how to do it
|dw:1335428318455:dw| do it from 0 to ω/4π
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