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sq. rt. of (3x - 2) = x - 2
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lol really?
x^2 -4x +4 = 3x-2
x^2 -7x +6
=0
then... \[{x_{1/2}} = \frac{{ - b \pm \sqrt {{b^2} - 4ac} }}{{2a}}\]
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whats funny ?
Good question @tana
(x-6)(x-1)=0 ==> x=6 or x=1
now answer my question... Are the Euler-Mascheroni constant...
yes
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lol^
nice one
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