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OpenStudy (anonymous):
Integral of x^2(x^3 + 1)^1/2
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OpenStudy (anonymous):
dude...
OpenStudy (anonymous):
too easy
OpenStudy (anonymous):
do it yourself lol
OpenStudy (experimentx):
suppose u =x^3 + 1, du = 3x^2 dx
OpenStudy (anonymous):
this is indefinite
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