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Can i derive from this tanx=sinx/cos this equation? cosx = sinx / tanx
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impossible
Yup
Just multiply by cosx and divide by tanx, assuming both are not zero. You will get: \(\LARGE \tan{x} \cos{x} = \sin {x} \rightarrow \cos{x} = \frac{\sin{x}}{\tan{x}}\)
easy stuff lol...
And I did a typo, I meant dividing by cos, to get tan(x) = sin(x)/cos(x)
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I wrote one thing and did another in the equation, haha.
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