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Multiply and simplify: 8/x^2 x^4/4x A)4x^2 B)2x C) x
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\[\LARGE {8\over x^2}\cdot {x^4\over 4x }\] is there multiplication between fractions? (:
Yesss! Just like how you have it! :)
ok... first you are supposed to know this formula: \[\LARGE {8\over x^2 }\cdot {x^4\over 4x}={8x\over 4}\cdot {\cancel{x^3}\over \cancel{x^3} } \] what do you get now ? :)
\[8\over x^2\]* \[ x^4\over4x\]
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