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Solve for b. (sqrt[b^4/25] = 4)
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\[\sqrt{b ^{4}/25} = 4\]
square on both sides..
\[B ^{4}/25 = 4^2\]
\[b ^{4}/25 = 16\]
ok now simplify!
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\[\LARGE \sqrt{\frac{b^4}{25}}=4\] \[\LARGE \frac{\sqrt{b^4}}{\sqrt{25}}=4\] \[\LARGE \frac{b^2}{5}=4\] \[\LARGE b^2=20\] \[\LARGE b=?\]
or you could do it that way :D..
is the same :) ..
find the sqrt of both sides. B and 4.47 B = 4.47?
\[\LARGE b^2=20\] \[\LARGE b=\pm\sqrt{20}\] \[\LARGE b=\pm\sqrt{4\cdot 5}\] \[\LARGE b=\pm2\sqrt{5}\]
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A. 2 B. \[\pm5\sqrt{2}\] C. 3 D. \[\pm2\sqrt{5}\]
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