Question

Find the solution to the equation
64^(x – 3) =4^2x.

Answer 1

\[64^{(x-3)} = 4^{2x}\]
\[4^{3(x-3)} = 4^{2x}\]
so 3x-3 = 2x
3x-2x = 3
x = 3

Answer 2

what method di you use

Answer 3

i just made the base of LHS =RHS
then the power of LHS should be equal to RHS

Answer 4

Um, 3x-9=2x-> Answer is 9