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Mathematics 17 Online
OpenStudy (anonymous):

For QPS find the sine, cosine,and tagent of P I have the diagram on the chat on this question

OpenStudy (anonymous):

OpenStudy (anonymous):

Please look at these diagrams: http://www.mathsisfun.com/geometry/unit-circle.html Understand that sin is the vertical component. What is cosine? What is tangent?

OpenStudy (anonymous):

can u give me the answer cause I need help and have to get this done fast and I will look at it thanks

OpenStudy (anonymous):

Okay, divide all the side of the triangle by the hypotenuse. The result is a new triangle of radius one. However, since we divided them all by the same number, the new triangle is proportional to the old one. That is, the new one has the SAME theta angle. Now on the new triangle, we take tan = sin / cos.

OpenStudy (anonymous):

ok then what do u do after theat

OpenStudy (anonymous):

That's it.

OpenStudy (anonymous):

then whats the correct answer?

OpenStudy (anonymous):

It seriously only takes 1 minute to understand the diagram. You should look at it. Sine is the VERTICAL, cosine is the HORIZONTAL. I already told you tangent.

OpenStudy (anonymous):

then the correctr anser is b? am I correct and if not can u tell me what I did wrong?

OpenStudy (anonymous):

You are correct except you made the small error that tan = cos / sin. That is NOT TRUE. The CORRECT formula is tan = sin / cos. Therefore the answer is not b.

OpenStudy (anonymous):

The answer is c.

OpenStudy (anonymous):

ok thats what I got yey thanks :P)

OpenStudy (anonymous):

np

OpenStudy (anonymous):

The triangle shown in forqpsfindthesine.docx is not a right triangle.\[14^2\neq 5^2+9^2 \]

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