Question

identify the 31st term of an arithmetic sequence where a1= 26 and a22 = -226

Answer 1

a22 = a1 + 21d
-226 = 26 + 21d
21d = -252
d = -12

31st term = 26 + (-12)30
= 26 - 360 = - 334

Answer 2

thankk you

Answer 3

find the common difference using the 22 term

use the term formula

\[T _{n} = a + (n -1)d\]

-226 = 26 + (22-1)d

-226 = 26 + 21d

21d = -252

d = -12

then for term 31

\[T _{31} = 26 + (31 -1)\times -12\]

\[T _{31} = 26 - 360\]

\[T _{31} = - 334\]

Answer 4

thats ok - i hope you can now be more confident in solving these
practice some

Answer 5

im trying, its just hard teaching myself, also im not good with word problems