What are the magnitude and direction of the electric force on an electron in a uniform electric field of strength 2360 N/C that points due east?

I understand the calculation of F = QE = 3.78 x 10^-16

How do I determine the direction?

Question

What are the magnitude and direction of the electric force on an electron in a uniform electric field of strength 2360 N/C that points due east?

I understand the calculation of F = QE = 3.78 x 10^-16

How do I determine the direction?

experimentx · Answer

direction of force is opposite as direction of field.

F = QE ,and Q = 1.6*10^-19

experimentx · Answer

the direction of force is opposite of the field because our charge is negative.
and the field flows from positive to negative.

anonymous · Answer

awesome, that clears up things! thanks