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MIT 18.01 Single Variable Calculus (OCW)
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10+3/a=5^a
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Taking log on both sides of base 5 probably helps is what I did ..
Taking natural log on both sides: \[\ln{10} + \ln{\frac3a} = \ln{5^a}\]\[\ln10 + \ln3 - \ln a = a \times \ln 5 \]Differentiating both sides, we have: \[0 + 0 - 1 / a = \ln 5\]\[a=-\frac{1}{\ln5}\]
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