Question

find the soloution of the system:
y= x^2 - 2x - 2
y= 4x + 5

Answer 1

2x = x^2 - y - 2.... SO
4x = 2x^2 - 2y - 4

y = (2x^2 - 2y - 4) + 5
y = 2x^2 - 2y - 4 + 5
3y = 2x^2 + 1
CAN YOU SOLVE NOW SUBSTITUTING x?

Answer 2

i still need help, i dont understand.

Answer 3

X=7 Y=33
X=-1 Y=1

Answer 4

thanks:)

Answer 5

x=7 y=33
x=-1 y=1