Question

The rate of change of y with respect to t is 3 times the value of the quantity 2 less than y. Find an equation for y, given that y = 212 when t = 0.
You get:

A. y=212e^3t-2
B. y=214e^3t-2
C. y=210e^3t+2
D. y=212e^3t+2
E. y=210e^3t-2

Please see attachment.

Answer 1

C.

Answer 2

Solve the following for y(t):\[y'(t)=3 (y(t)-2) \]The solution to the above is:\[c_1 e^{3 t}+2 \]