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Mathematics 19 Online
OpenStudy (anonymous):

An equilateral triangle, a square and a regular hexagon are connected as shown. If the sides of all figures are 12 cm and the apothem of the hexagon is 10.4 cm, find the area of the entire figure. Round your answer to the nearest tenth. if a drawing is necessary il draw

OpenStudy (anonymous):

and im looking for the formula

Directrix (directrix):

>as shown- Is there a diagram?

OpenStudy (anonymous):

yes hold on

OpenStudy (anonymous):

|dw:1335572882198:dw|

OpenStudy (anonymous):

i could use the formula i used for the decagon right?

OpenStudy (anonymous):

5(5.54x3.6)= 99.72

OpenStudy (anonymous):

?(10.4 x 12)

OpenStudy (anonymous):

wait i was looking at that

OpenStudy (anonymous):

Triangle = (12^2 Sqrt[3])/4 Square = 12 (12) Hexagon = 6 Triangle Area = Triangle + Square + Hexagon You will get \[ 144+252 \sqrt{3} \]

OpenStudy (anonymous):

i got 686.4

OpenStudy (anonymous):

n0 580.48 when rounded ?

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

well thank you.

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