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4(cos150+i sin150)
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This is the polar form of a complex number. What is the question?
4 e^(150i)
the question is write the complex number in rectangular form
\[a+ib=4\cos 150+i4\sin 150\] \[4\cos 150=a\] \[4\sin 150=b\] \[4(\cos 150+i \sin 150)=-3.464+i2\]
finally got it too lol thankz
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[square root of 7(cos 35 + i sin 35)]^6
write in standard form a+bi
cos150= cos(180-30)= -cos 30=-sqrt3/2 simimilarly sin150=sin30=1/2 noe try to solve urself
Using Demoivre's Theorem the expression becomes:\[(\sqrt{7})^{6}(\cos (6\times 35)+i \sin (6\times 35))\]
so here arguement is 30degrees or pi/6 radian now use euler's form n u'll get |dw:1335602161781:dw|
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