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Solving the exponential equation algebraically, e^(2x)-6e^x=-5 I know I have to take a natural log of something, but nothing else.
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I typed it into Wolfram and it said, it was log5 as the answer, but I can't understand how it got to that.
take e^x = A |dw:1335607090127:dw| hence e^x = 1 &&&& e^x=5 now apply log to get your answer...
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