Question

what r the steps to solve: 2^x^2 4^-4x+4=1/16

Answer 1

Can you draw it?

Answer 2

\[\LARGE [(2^{x})^{2}][46 ^{-4x + 4}] = {1 \over 16} \]
\[\LARGE \text {Is this what you mean?} \]

Answer 3

just 4, not 46

Answer 4

Can you draw it?

Answer 5

no

Answer 6

This is dealing with powers (exponents).
1/16 can be written as 2^-4 so just rewrite all as powers of 2 and compare exponents to find x

Answer 7

TY