Question

can someone solve these for me?
the problem is in the comments

Answer 1

easy

Answer 2

Hint:
\[\text{a. }a^4-b^4=(a^2)^2-(b^2)^2\\
\text{b. }3x^2+7x-6=(3x-\text{something})(x+\text{something else})\]
where something*something else=-6. Try out all the possibilities; you'll soon get the answer.

Answer 3

is the first one (a-b)(a+b)(a^2+b^2)?

Answer 4

an the second one is (x+3)(3x-2)

Answer 5

Yes. :D

Answer 6

thank you sooo much! :)

Answer 7

No problem. :D