Question

Solve the system of equations y= -0.04x^2 + 8.3x , y=1.12x + 1.6

Answer 1

BY EQUATING THE EQUATIONS
-0.04X^2+8.3X=1.12X+1.6
0.04X^2-7.18X+1.6
THEN FACTORIZE

Answer 2

y= -0.04x^2 + 8.3x -(1)
y=1.12x + 1.6 -(2)
Put (1) into (2)
1.12x + 1.6 = -0.04x^2 + 8.3x
0.04x^2 - 7.18x + 1.6 =0
4x^2 - 718x + 160 =0
Oh.. then use quadratic formula to solve it!

Answer 3

\[x = \frac{-b \pm \sqrt {b^2-4ac}}{2a}\]
Put a = 4, b= -718 and c=160 into the above formula. See what you can get!~

Answer 4

I have fell off the cliff now!@!

Answer 5

Don't worry, superman will save you :)

Answer 6

Before superman arrives, let save yourself first :)
\[x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}\]\[x = \frac{-(-718) \pm \sqrt{(-718)^2-4(4)(160)}}{2(4)}\]\[x = \frac{718 \pm \sqrt{512964}}{8} \]\[x= \frac{359 \pm \sqrt{128241}}{4} \]\[=\frac{359 \pm 3\sqrt{14249}}{4} \]
It's really ...not elegant..