Question

Solve by factoring:
10t2 – t − 2 = 0

Answer 1

Look for two terms to whom,
when you add you get -1
and when multiply -20

Answer 2

10t^2 – t − 2 = 0
10t^2 -5t + 4t -2 =0
5t( 2t-1) + 2(t-1) =0
(2t-1)(5t+2) =0
(2t-1)=0 or (5t+2) =0
Can you do it from here?

Answer 3

no

Answer 4

I am having difficulty with quadratics

Answer 5

Where are you stuck?

Answer 6

I will go back and review. thanks for the help

Answer 7

I can guide you step by step if you stuck..
Sure.

Answer 8

please it would be greatly appreciated.

Answer 9

Ok,
so first step,
look at the equation it says,
:
10t2 – t − 2 = 0
a = 10
b = -1
c = -2

agree?

Answer 10

yes correct

Answer 11

Ok, next step is to look for two terms..

First,
when you add you get -1
and when multiply -20

[How i got -1?
A: it's the value of b.

How i got -20
it's the value of a * c.
10*-2 = -20

Agree?

Answer 12

ok got that

Answer 13

So now two terms = -5 and 4
When we add them, we get -1 and when we multiply -20.

agree?

Answer 14

yes

Answer 15

Ok, so,

10t^2 – t − 2 = 0
break the middle term into two numbers we just figured..
10t^2 -5t + 4t -2 =0

Answer 16

ok got that

Answer 17

Now, follow @RolyPoly 's working. :)

Answer 18

ok, thank you for helping me:)

Answer 19

No worries.