Question

Given g(x) = x+1
x−1 , solve g(x) = 0

Answer 1

Since g(x) = 0

g(x) = x+1
0 = x+ 1

Solve.

Answer 2

can you rewrite it ?
what is x-1 ?

Answer 3

Sorry given g(x)= x+1/x-1, solve g(x)=0

Answer 4

\[g(x) = \frac{x+1}{x-1}\]
\[0 = \frac{x+1}{x-1}\]

Answer 5

ok than first of all you need push the restriction for x when the denominator will be equal zero

Answer 6

because than the fraction will be undefined

Answer 7

ok ?

Answer 8

so what will be ?

Answer 9

Rose ! are you there ?