Question

all terms in a geometric sequence are positive integers, and the first 3 terms are n, n+3 and 2n+6. what is the 4th term of this sequence?

Answer 1

in a geometric sequence the common ratio = 2nd/term / first ( ar / a) so here:
common ratio = n+3 / n
so 4th term
= (2n + 6) * ( n+3) / n

= (2n^2 + 12n + 18) / n
= 2n + 12 + 18/n

Answer 2

thx

Answer 3

yw