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Mathematics 10 Online
OpenStudy (anonymous):

(1-sinx)^1/2 ^ Evaluate this indefinite integral

OpenStudy (anonymous):

experimentX are you a mathematician?

OpenStudy (experimentx):

1 = sin^2 x/2 + cos^2 x/2 sin x = 2 sin x/2 cos x/2

OpenStudy (anonymous):

Wait I do not get it...

OpenStudy (experimentx):

put that value of 1 in and sin x in the expression, and it becomes (sin x/2 - cos x/2)^2

OpenStudy (anonymous):

I don't see how your explanation is going to get us anywhere..

OpenStudy (anonymous):

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