Question

I am not understanding these types of problems. 27-a^3b^6 Help!

Answer 1

what you have to do there? ...

Answer 2

maybe..
\[\LARGE 27-a^3b^6=3^3-(ab^2)^3=...\]

Answer 3

it looks like the difference of cubics...

\[27 = 3^3\]

\[a^3b^6 = (ab^2)^3\]

\[(3-ab^2)(9 + 3ab^2 + a^2b^4)\]

Answer 4

yeah.. it looks like. :)

Answer 5

Yeah I thought it was difference of cubes but I can't seem to factor it correctly once I use the formula.

Answer 6

Can someone walk me through it. I have a ton of these problems. And I am doing something wrong.

Answer 7

post new question on wall, not here :)