Question

Can someone walk me through factoring the sum/difference of cubes? ex. 27-a^3b^6

Answer 1

This the problem?

\[27 - a^{3}b^6\]

Answer 2

Yes

Answer 3

Look at this link, http://www.ehow.com/how_4500295_factor-cube-functions.html

Focus on factoring quads first, if you haven't already.

Answer 4

\[(a^3-b^3)=(a-b)(a^2+ab+b^2)\]
this is the formula you will need.
You need to determine what a and b are: