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Why is problem #5 NOT 2/3?
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The answer is 2/9 by the way...
(u/v)' = (u'v - v'u)/v^2
must be 2/9 u = g(x), v=x
o i gotta use the product rule prior to plugging in anything
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i mean quotient
now im getting -2/9 ugh
= (2 *3 - 4 )/ 3^2
(g'(x) x - g(x)/x^2 = (2*3 - 4)/3^2=2/9
o ok. i did the numerator backwards.
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