Question

Solve the equation

x^2+2x-48=0

Answer 1

look at the first and last terms
x^2 and -48
consider the factors of each
(x, x) (1, 2, 3, 4, 6, 8, 12, 16, 48)
we have to times the factors of both and add them together to give the middle number +2x
so therefore it's (x+8)(x-6)
if u times it out and collect like terms u should get the original equation.