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OpenStudy (anonymous):
if you have an equation h= -0.0425d^2 + 3.75d at a horizontal distance of 20m from the vertex, what is the height of the arch, to the nearset tenth the horizontal distance is d and h is the height the question is talking about a arch
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OpenStudy (mertsj):
The x coordinate of the vertex is -3.75/-.0850=44.11 Twenty units from that is 66.11 -.0425(66.11)^2+3.75(66.11)=62.2 ft
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