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Solve x^2-4x=32
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\[x^2-4x=32\] \[(x-2)^2=32+4=36\] \[x-2=\pm\sqrt{36}=\pm6\] \[x=6+2=8\] \[x=-6+2=-4\]
x^(2)-4x=32 x^(2)-4x-32=0 (x+4)(x-8)=0 x=-4,8
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