Question

\[\sqrt{b^2-4}=b-2\]
symbolically, im not liking these lol

Answer 1

square both isdes and get
\[b^2-4=(b-2)^2\]
\[b^2-4=b^2-4b+4\]
\[-4=-4b+4\]
\[-8=-4b\]
\[b=2\] and we check

Answer 2

have to check because we squared.
replace x by 2, get zero on both sides so it is right

Answer 3

how do you do these so fast? it is like pulling teeth with me

Answer 4

you have a square root, so what choice do you have but to square? the rest is algebra practice

Answer 5

which is my weak spot