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OpenStudy (anonymous):
if r and s are solutions of x^2 + 6x - 2 = 0, what is the value of r^3 + s^3.
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OpenStudy (campbell_st):
use the quadratic formula to find the roots of the quadratic \[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\] a = 1, b = 6 and c = -2 the two values you get for x... will be r and s... then cube each and add the answers
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